2x^2-2x+8=x^2-4

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Solution for 2x^2-2x+8=x^2-4 equation: 



2x^2-2x+8=x^2-4

We move all terms to the left:

2x^2-2x+8-(x^2-4)=0

We get rid of parentheses

2x^2-x^2-2x+4+8=0

We add all the numbers together, and all the variables

x^2-2x+12=0

a = 1; b = -2; c = +12;
Δ = b2-4ac
Δ = -22-4·1·12
Δ = -44
Delta is less than zero, so there is no solution for the equation

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